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Nominations for sequence A400000 are open, see here.
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30 = 2*3*5 is the first spheric number, so a(1) = 30.
allocated for Jonathan SondowFirst of the smallest n consecutive sphenic numbers A007304.
30, 230, 1309
1,1
Every 4th consecutive number is divisible by 4 = 2*2 and therefore is not sphenic, so a(n) does not exist for n >= 4.
Wikipedia, <a href="https://en.wikipedia.org/wiki/Sphenic_number">Sphenic number</a>
30 = 2*3*5 is the first spheric number, so a(1) = 30.
The first case of two consecutive sphenic numbers is 230 = 2*5*23 and 231 = 3*7*11, so a(2) = 230.
The first case of three is 1309 = 7*11*17, 1310 = 2*5*131, and 1311 = 3*19*23, so a(3) = 1309.
Cf. A007304.
allocated
nonn,fini,full
Jonathan Sondow, Oct 17 2017
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allocated for Jonathan Sondow
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