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Improve name and comment for _get_redirect_url().
  • Loading branch information
nascheme committed Jun 16, 2022
commit f99e80b935613e802ade6f9d85e8e8c3595456a5
10 changes: 8 additions & 2 deletions Lib/http/server.py
Original file line number Diff line number Diff line change
Expand Up @@ -678,7 +678,7 @@ def send_head(self):
path = self.translate_path(self.path)
f = None
if os.path.isdir(path):
new_url = _add_trailing_slash(self.path)
new_url = _get_redirect_url(self.path)
if new_url:
# redirect browser - doing basically what apache does
self.send_response(HTTPStatus.MOVED_PERMANENTLY)
Expand Down Expand Up @@ -878,10 +878,16 @@ def guess_type(self, path):
return 'application/octet-stream'


def _add_trailing_slash(path):
def _get_redirect_url(path):
"""Returns URL with trailing slash on path, if required. If not required,
returns None.
"""
# It would be simpler to use urllib.parse.urlsplit() here. However, the
# 'path' is not truly a URI in that it can't have a scheme or netloc. We
# need to avoid parsing it incorrectly. For example, as reported in
# gh-87389, a path starting with a double slash should not be treated as a
# relative URI. Also, a path with a colon in the first component could
# also be parsed wrongly.
path, _, fragment = path.partition('#')
path, _, query = path.partition('?')
if path.endswith('/'):
Expand Down