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2 changes: 1 addition & 1 deletion Lib/codeop.py
Original file line number Diff line number Diff line change
Expand Up @@ -87,7 +87,7 @@ def _maybe_compile(compiler, source, filename, symbol):
# Catch syntax warnings after the first compile
# to emit SyntaxWarning at most once.
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with warnings.catch_warnings():
warnings.simplefilter("error", SyntaxWarning)
warnings.simplefilter("error")

try:
code1 = compiler(source + "\n", filename, symbol)
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13 changes: 8 additions & 5 deletions Lib/test/test_codeop.py
Original file line number Diff line number Diff line change
Expand Up @@ -307,14 +307,17 @@ def test_filename(self):

def test_warning(self):
# Test that the warning is only returned once.
with warnings_helper.check_warnings((".*literal", SyntaxWarning)) as w:
compile_command("0 is 0")
self.assertEqual(len(w.warnings), 1)
with warnings_helper.check_warnings(
(".*literal", SyntaxWarning),
(".*invalid", DeprecationWarning),
) as w:
compile_command(r"'\e' is 0")
self.assertEqual(len(w.warnings), 2)

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Would it be possible to another test which only emits a single warning? For example, keep the existing "0 is 0" test, but add your new test as a new one (don't replace the existing one).

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check_warnings checks that each of the two warnings is called, so that 2 must be 1+1 and not 2+0, so the above is, in a sense, two independent tests. We are not testing builtin compile, but that compile_command only lets 1+1 of the 3+3 warnings pass to the caller.


# bpo-41520: check SyntaxWarning treated as an SyntaxError
with self.assertRaises(SyntaxError):
with warnings.catch_warnings(), self.assertRaises(SyntaxError):
warnings.simplefilter('error', SyntaxWarning)
compile_command('1 is 1\n', symbol='exec')
compile_command('1 is 1', symbol='exec')


if __name__ == "__main__":
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Original file line number Diff line number Diff line change
@@ -1 +1 @@
Fix :mod:`codeop` regression: it no longer ignores :exc:`SyntaxWarning`.
Fix :mod:`codeop` regression that prevented turning compile warnings into errors.