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Lesson6 #861

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ac3a0af
Easy level has to be done.
larcefox Aug 17, 2019
7e3fe1a
Hard level has to be done.
larcefox Aug 17, 2019
683b0ff
Normal level has to be done.
larcefox Aug 17, 2019
8c1cfc8
Easy level has to be done.
larcefox Aug 17, 2019
3ec2844
Easy level has to be done.
larcefox Aug 18, 2019
f0720de
Normal level has to be done.
larcefox Aug 18, 2019
fedb597
HW 4: Easy and normal.
larcefox Aug 26, 2019
a3084bb
HW 4: Easy and normal. Added the "without re way"
larcefox Aug 26, 2019
954bb02
HW 5: All levels are done.
larcefox Aug 28, 2019
6daba6a
HW 5: All levels are done. Added pwd command and changed ls function.
larcefox Aug 29, 2019
58026d4
HW 6: Easy and Normal levels.
larcefox Sep 2, 2019
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Normal level has to be done.
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@larcefox
larcefox committed Aug 17, 2019
commit 683b0ff0890a1d30d09f2ed5408aaa564a002685
41 changes: 40 additions & 1 deletion lesson01/home_work/hw01_normal.py
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@@ -1,5 +1,7 @@

__author__ = 'Ваши Ф.И.О.'
__author__ = 'Субботин Андрей Владимирович'

from math import sqrt

# Задача-1: Дано произвольное целое число, вывести самую большую цифру этого числа.
# Например, дается x = 58375.
Expand All @@ -10,6 +12,20 @@
# * постарайтесь решить задачу с применением арифметики и цикла while;
# * при желании и понимании решите задачу с применением цикла for.

num = 7854632568455841123657
max_num = 0

while num:
num_element = num % 10
if num_element == 9:
print("Maximum number is 9")
break
else:
if num_element > max_num:
max_num = num_element
num = num // 10
else:
print(max_num)

# Задача-2: Исходные значения двух переменных запросить у пользователя.
# Поменять значения переменных местами. Вывести новые значения на экран.
Expand All @@ -18,10 +34,33 @@
# * постарайтесь сделать решение через действия над числами;
# * при желании и понимании воспользуйтесь синтаксисом кортежей Python.

a = input('Enter first number: \n')
b = input('Enter second number: \n')

a, b = b, a
print ('Now first number is: ', a, ' and the secoend is: ', b)

# Задача-3: Напишите программу, вычисляющую корни квадратного уравнения вида
# ax² + bx + c = 0.
# Коэффициенты уравнения вводятся пользователем.
# Для вычисления квадратного корня воспользуйтесь функцией sqrt() модуля math:
# import math
# math.sqrt(4) - вычисляет корень числа 4

print('Введите коэффициенты для квадратного уравнения (ax² + bx + c = 0):')
a = float(input('a =\n '))
b = float(input('b =\n '))
c = float(input('c =\n '))

discr = b ** 2 - 4 * a * c
print('Дискриминант D = %.2f' % discr)

if discr > 0:
x1 = (-b + sqrt(discr)) / (2 * a)
x2 = (-b - sqrt(discr)) / (2 * a)
print('x1 = %.2f \nx2 = %.2f' % (x1, x2))
elif discr == 0:
x = -b / (2 * a)
print('x = %.2f' % x)
else:
print('Корней нет')