Multiplying a MIMO TransferFunction object by the Python float 1.0 appears to multiply it by a matrix of ones, rather than the identity matrix. The same goes for any scalar. Is this the intended behaviour? I checked in the documentation and didn't see anything.
Example:
import control
G = control.TransferFunction(
[
[[87.8], [-86.4]],
[[108.2], [-109.6]],
],
[
[[1, 1], [1, 1]],
[[1, 1], [1, 1]],
],
)
I = control.TransferFunction(
[
[[1], [1]],
[[1], [1]],
],
[
[[1], [1]],
[[1], [1]],
],
)
print(G)
print(1 * G)
print(I * G)
Multiplying a MIMO
TransferFunctionobject by the Python float1.0appears to multiply it by a matrix of ones, rather than the identity matrix. The same goes for any scalar. Is this the intended behaviour? I checked in the documentation and didn't see anything.Example: