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1046.最后一块石头的重量.py

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# 每次取出最大的两个元素相减，结果不为0则添加到列表中

class Solution(object):

def lastStoneWeight(self, stones):

while len(stones) > 1:

y = stones.pop(stones.index(max(stones)))

x = stones.pop(stones.index(max(stones)))

if x < y:

stones.append(y-x)

return stones[0] if stones else 0