This would return Axis[:].difference(Group). For example, ```python >>> a = Axis('a=a0..a4') >>> ~a['a0,a3'] a['a1', 'a2', 'a4'] ```
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gdementen commentedon Sep 29, 2017
Easy but not possible with current group API (because ~ is already defined). We need #23.
gdementen commentedon Oct 23, 2017
removed easy label to avoid a new contributor trying to tackle this before #23 is done