ML_Learnings/Python_Coding_Challenges/divby3and5_p1.py at main · indhra/ML_Learnings

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# -*- coding: utf-8 -*-

"""

Created on Tue Mar 1 10:00:51 2022

@author: INDHRNA

"""

If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.

Find the sum of all the multiples of 3 or 5 below 1000.

"""

from time import time

start = time()

import numpy as np

import pandas as pd

from numpy import arange, mod

from pandas import Series

#%%%

if __name__ == '__main__':

numb = 1000

lis = []

numbers = arange(0,numb)

lis = [(num) for count,num in enumerate(numbers) if (num%3==0) or (num%5==0) ]

sume = np.sum((lis))

print(sume)

df = Series(numbers)

dff = df [(mod(df ,3)==0) | (mod(df ,5)==0)]

print(dff.sum())

print(f'time taken for execution is : {time()-start}')