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future-builder007
algorithm_code
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algorithm_code
/
code
/
array
/
02.js
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master
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algorithm_code
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code
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array
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02.js
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// leetcode 914 卡牌分组
/**
* 给定一副牌,每张牌上都写着一个整数
* 此时,你需要选定一个数字X,使我们可以将整副牌按下述规则分成1组活更多组:
* * 每组都有X张牌
* * 组内所有的牌上都写着相同的整数
* 仅当你可选的X >=2时返回 true
* 示例 1 :
* 输入: [1,2,3,4,4,3,2,1]
* 输出: true;
* 解释:可行的分组是 [1,1],[2,2],[3,3],[4,4]
* 示例 2 :
* 输入: [1,1,1,2,2,2,3,3]
* 输出: false;
* 解释:没有满足要求的分组
*/
export
default
(
arr
)
=>
{
// 对这副牌进行排序,升序、降序都可以
arr
.
sort
(
(
a
,
b
)
=>
a
-
b
)
;
let
min
=
Number
.
MAX_SAFE_INTEGER
let
dst
=
[
]
;
// 保存分组后的数组
let
result
=
true
;
// 进行分组
for
(
let
i
=
0
,
len
=
arr
.
length
,
tmp
=
[
]
;
i
<
len
;
i
++
)
{
tmp
.
push
(
arr
[
i
]
)
;
for
(
let
j
=
i
+
1
;
j
<
len
;
j
++
)
{
if
(
arr
[
i
]
==
arr
[
j
]
)
{
tmp
.
push
(
arr
[
j
]
)
;
}
else
{
if
(
min
>
tmp
.
length
)
{
min
=
tmp
.
length
;
}
dst
.
push
(
[
]
.
concat
(
tmp
)
)
;
tmp
.
length
=
0
;
// 清空临时数组;
i
=
j
;
// 重点,跳到不满足分组当前位置
break
}
}
}
// 检查所有分组的长度都是最小分组长度的整数倍
dst
.
every
(
item
=>
{
if
(
item
.
length
%
min
!==
0
)
{
return
false
}
;
return
true
;
}
)
return
result
}
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