OctaveDouble precision differences due to octave hex representation  #3

    @Test
    public void testPrecision() {
    	final OctaveEngine octave = new OctaveEngineFactory().getScriptEngine();
    	octave.eval("format long");
    	octave.eval("a = (1/3) * 0.29");
    	OctaveDouble a = octave.get(OctaveDouble.class, "a");
    	//This assertion will fail.
    	//On evaluation, the console will report "a =  0.0966666666666667",
    	//But retrieving the value back from the wrapper reports the native-hex value cast to a double
    	assertEquals(0.096666666666667, a.get(1), 0.0);
    }