Repository navigation
Expand file tree
/
Copy pathex_mod_subtool_export.py
More file actions
87 lines (67 loc) · 3.24 KB
/
Copy pathex_mod_subtool_export.py
File metadata and controls
87 lines (67 loc) · 3.24 KB
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
"""Demonstrates how to batch export all sub-tools in a ZBrush file to OBJ format.
This script is meant to be used with as a command line argument of ZBrush. Its invocation
syntax is:
$ZBRUSH_BIN -script <path_to_this_script> <path_to_output_dir> <path_to_zbrush_file_to_load>
For example:
"/Applications/Maxon ZBrush 2026.1/ZBrush.app/Contents/MacOS/ZBrush" \
-script \ "/Users/alice/Downloads/zbrush-sdk/examples/modeling/ex_mod_subtool_export.py" \
"/Users/alice/Documents/temp/sub_tools" \
"/Applications/Maxon ZBrush 2026.1/Lightbox/Projects/DemoSoldier.ZPR"
"""
__author__ = "Javier Edo"
__date__ = "21/08/2025"
__copyright__ = "Maxon Computer"
import os
import sys
import zbrush.commands as zbc
def export_subtools(export_directory=""):
if not os.path.isdir(export_directory):
print(f"Invalid export directory specified: {export_directory}")
return False
# Get the number of SubTools in the current tool
subtool_count = zbc.get_subtool_count()
if subtool_count == 0:
print("No SubTools found to export.")
return False
exported_files = 0
# Loop through all SubTools
for i in range(subtool_count):
# Set the active SubTool
zbc.select_subtool(i)
# Check if the SubTool is visible (status flag 0x01 means visible)
status = zbc.get_subtool_status()
if status & 0x01:
# Get the full path of the active tool, which includes the SubTool name
full_tool_path = zbc.get_active_tool_path()
subtool_name = full_tool_path.rsplit('/')[-1] # Extract name after the last slash
# Create the final output path for the OBJ file
output_path = os.path.join(export_directory, f"{subtool_name}.obj")
# Set this as the next file name for ZBrush's exporter
zbc.set_next_filename(output_path)
# Press the "Export" button in the Tool palette
zbc.press("Tool:Export")
print(f"Exported SubTool '{subtool_name}' to {output_path}")
exported_files += 1
return exported_files
def export_subtools_with_ui(export_directory=""):
if not os.path.isdir(export_directory):
save_path = zbc.ask_filename("*.obj", "Select a folder and enter a dummy file name",
"Choose Export Directory")
if not save_path:
zbc.message_ok("Export cancelled by user.")
return False
export_directory = os.path.dirname(save_path)
exported_files = export_subtools(export_directory)
if exported_files > 0:
zbc.message_ok(f"Export complete! {exported_files} SubTools were saved to:\n{export_directory}")
else:
zbc.message_ok("No SubTools were exported.")
if __name__ == '__main__':
if "-script" not in sys.argv or (sys.argv.index("-script") + 1)>= len(sys.argv):
print("This script requires the -script flag followed by the args to the script.")
sys.exit(1)
# args to actual script (put after the -script "/path/to/script.py" args)
script_args = sys.argv[sys.argv.index("-script") + 2:]
export_directory = script_args[0] if script_args else ""
ret_code = not export_subtools(export_directory)
sys.exit(ret_code)