Medium
A trie (pronounced as "try") or prefix tree is a tree data structure used to efficiently store and retrieve keys in a dataset of strings. There are various applications of this data structure, such as autocomplete and spellchecker.
Implement the Trie class:
Trie()Initializes the trie object.void insert(String word)Inserts the stringwordinto the trie.boolean search(String word)Returnstrueif the stringwordis in the trie (i.e., was inserted before), andfalseotherwise.boolean startsWith(String prefix)Returnstrueif there is a previously inserted stringwordthat has the prefixprefix, andfalseotherwise.
Example 1:
Input
["Trie", "insert", "search", "search", "startsWith", "insert", "search"]
[[], ["apple"], ["apple"], ["app"], ["app"], ["app"], ["app"]]
Output: [null, null, true, false, true, null, true]
Explanation:
Trie trie = new Trie();
trie.insert("apple"); trie.search("apple"); // return True
trie.search("app"); // return False
trie.startsWith("app"); // return True
trie.insert("app");
trie.search("app"); // return True
Constraints:
1 <= word.length, prefix.length <= 2000wordandprefixconsist only of lowercase English letters.- At most
3 * 104calls in total will be made toinsert,search, andstartsWith.
To solve the task, here are the steps for implementing the Trie (Prefix Tree) problem:
-
Define the TrieNode Class:
- Define a class named
TrieNodeto represent each node in the trie. - Each node will have a dictionary to store child nodes, indicating possible characters that can follow the current node.
- Additionally, each node will have a boolean flag to mark whether it represents the end of a word.
- Define a class named
-
Initialize the Trie Class:
- Implement the
__init__method for the Trie class to initialize an empty trie with a root node.
- Implement the
-
Implement the Insert Method:
- Implement the
insertmethod to insert a word into the trie. - Start from the root node and iterate through each character in the word.
- Check if the character exists as a child of the current node. If not, create a new node for it.
- Move to the child node and repeat the process for the next character.
- After processing all characters, mark the last node as the end of the word.
- Implement the
-
Implement the Search Method:
- Implement the
searchmethod to check if a word exists in the trie. - Start from the root node and iterate through each character in the word.
- If at any point, a character is not found as a child of the current node, return False.
- If all characters are found and the last node is marked as the end of a word, return True.
- Implement the
-
Implement the StartsWith Method:
- Implement the
startsWithmethod to check if there is any word in the trie that starts with a given prefix. - Follow a similar process as the search method, but return True as soon as all characters of the prefix are found, regardless of whether it forms a complete word.
- Implement the
-
Return Results:
- After implementing all methods, create an instance of the Trie class and perform the required operations according to the given input.
Here's a Python implementation:
class TrieNode:
def __init__(self):
self.children = {}
self.is_end_of_word = False
class Trie:
def __init__(self):
self.root = TrieNode()
def insert(self, word: str) -> None:
node = self.root
for char in word:
if char not in node.children:
node.children[char] = TrieNode()
node = node.children[char]
node.is_end_of_word = True
def search(self, word: str) -> bool:
node = self.root
for char in word:
if char not in node.children:
return False
node = node.children[char]
return node.is_end_of_word
def startsWith(self, prefix: str) -> bool:
node = self.root
for char in prefix:
if char not in node.children:
return False
node = node.children[char]
return True
# Example Usage
trie = Trie()
trie.insert("apple")
print(trie.search("apple")) # Output: True
print(trie.search("app")) # Output: False
print(trie.startsWith("app")) # Output: True
trie.insert("app")
print(trie.search("app")) # Output: TrueThis solution efficiently implements the Trie data structure and satisfies the requirements of the problem.