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| 1 | +package array; |
| 2 | + |
| 3 | +import java.util.ArrayList; |
| 4 | +import java.util.HashMap; |
| 5 | +import java.util.List; |
| 6 | +import java.util.Map; |
| 7 | + |
| 8 | +/** |
| 9 | + * Created by gouthamvidyapradhan on 11/04/2018. |
| 10 | + * Suppose Andy and Doris want to choose a restaurant for dinner, and they both have a list of favorite restaurants |
| 11 | + * represented by strings. |
| 12 | +
|
| 13 | + You need to help them find out their common interest with the least list index sum. If there is a choice tie between |
| 14 | + answers, output all of them with no order requirement. You could assume there always exists an answer. |
| 15 | +
|
| 16 | + Example 1: |
| 17 | + Input: |
| 18 | + ["Shogun", "Tapioca Express", "Burger King", "KFC"] |
| 19 | + ["Piatti", "The Grill at Torrey Pines", "Hungry Hunter Steakhouse", "Shogun"] |
| 20 | + Output: ["Shogun"] |
| 21 | + Explanation: The only restaurant they both like is "Shogun". |
| 22 | + Example 2: |
| 23 | + Input: |
| 24 | + ["Shogun", "Tapioca Express", "Burger King", "KFC"] |
| 25 | + ["KFC", "Shogun", "Burger King"] |
| 26 | + Output: ["Shogun"] |
| 27 | + Explanation: The restaurant they both like and have the least index sum is "Shogun" with index sum 1 (0+1). |
| 28 | + Note: |
| 29 | + The length of both lists will be in the range of [1, 1000]. |
| 30 | + The length of strings in both lists will be in the range of [1, 30]. |
| 31 | + The index is starting from 0 to the list length minus 1. |
| 32 | + No duplicates in both lists. |
| 33 | +
|
| 34 | + Solution:O(N) maintain index of each restaurant in a list using a HashMap, find the min sum of indices and list |
| 35 | + all the restaurants which match the min sum of indices |
| 36 | +
|
| 37 | + */ |
| 38 | +public class MinimumIndexSumOfTwoLists { |
| 39 | + /** |
| 40 | + * Main method |
| 41 | + * @param args |
| 42 | + */ |
| 43 | + public static void main(String[] args) throws Exception{ |
| 44 | + String[] A1 = {"Shogun", "Tapioca Express", "Burger King", "KFC"}; |
| 45 | + String[] A2 = {"Tapioca Express", "Shogun", "Burger King"}; |
| 46 | + String[] ans = new MinimumIndexSumOfTwoLists().findRestaurant(A1, A2); |
| 47 | + for(String s : ans){ |
| 48 | + System.out.println(s); |
| 49 | + } |
| 50 | + } |
| 51 | + |
| 52 | + public String[] findRestaurant(String[] list1, String[] list2) { |
| 53 | + int min = Integer.MAX_VALUE; |
| 54 | + List<String> result = new ArrayList<>(); |
| 55 | + if(list2.length == 0) return new String[0]; |
| 56 | + Map<String, Integer> index = new HashMap<>(); |
| 57 | + for(int i = 0; i < list2.length; i ++){ |
| 58 | + index.put(list2[i], i); |
| 59 | + } |
| 60 | + for(int i = 0; i < list1.length; i ++){ |
| 61 | + String s = list1[i]; |
| 62 | + if(index.containsKey(s)){ |
| 63 | + int sum = i + index.get(s); |
| 64 | + min = Math.min(min, sum); |
| 65 | + } |
| 66 | + } |
| 67 | + |
| 68 | + for(int i = 0; i < list1.length; i ++){ |
| 69 | + String s = list1[i]; |
| 70 | + if(index.containsKey(s)){ |
| 71 | + int sum = i + index.get(s); |
| 72 | + if(sum == min){ |
| 73 | + result.add(s); |
| 74 | + } |
| 75 | + } |
| 76 | + } |
| 77 | + String[] resArr = new String[result.size()]; |
| 78 | + result.toArray(resArr); |
| 79 | + return resArr; |
| 80 | + } |
| 81 | +} |
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