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Python
/
convert-a-number-to-hexadecimal.py
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LeetCode
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convert-a-number-to-hexadecimal.py
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# Time: O(logn)
# Space: O(1)
# Given an integer, write an algorithm to convert it to hexadecimal.
# For negative integer, two’s complement method is used.
#
# IMPORTANT:
# You must not use any method provided by the library which converts/formats
# the number to hex directly. Such solution will result in disqualification of
# all your submissions to this problem. Users may report such solutions after the
# contest ends and we reserve the right of final decision and interpretation
# in the case of reported solutions.
#
# Note:
#
# All letters in hexadecimal (a-f) must be in lowercase.
# The hexadecimal string must not contain extra leading 0s. If the number is zero,
# it is represented by a single zero character '0'; otherwise,
# the first character in the hexadecimal string will not be the zero character.
# The given number is guaranteed to fit within the range of a 32-bit signed integer.
# You must not use any method provided by the library which converts/formats the number to hex directly.
# Example 1:
#
# Input:
# 26
#
# Output:
# "1a"
# Example 2:
#
# Input:
# -1
#
# Output:
# "ffffffff"
class
Solution
(
object
):
def
toHex
(
self
,
num
):
"""
:type num: int
:rtype: str
"""
if
not
num
:
return
"0"
result
=
[]
while
num
and
len
(
result
)
!=
8
:
h
=
num
&
15
if
h
<
10
:
result
.
append
(
str
(
chr
(
ord
(
'0'
)
+
h
)))
else
:
result
.
append
(
str
(
chr
(
ord
(
'a'
)
+
h
-
10
)))
num
>>=
4
result
.
reverse
()
return
""
.
join
(
result
)
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